2x^2+50x-7900=0

Solution for 2x^2+50x-7900=0 equation:

2x^2+50x-7900=0

a = 2; b = 50; c = -7900;
Δ = b2-4ac
Δ = 502-4·2·(-7900)
Δ = 65700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{65700}=\sqrt{900*73}=\sqrt{900}*\sqrt{73}=30\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-30\sqrt{73}}{2*2}=\frac{-50-30\sqrt{73}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+30\sqrt{73}}{2*2}=\frac{-50+30\sqrt{73}}{4}
$